February 22 and 23
Showing posts with label francisM9-05. Show all posts
Showing posts with label francisM9-05. Show all posts
Scribe Post for March 10,2010
Wednesday, March 10, 2010
Hi 9-05 today as you know we learned about dividing polynomials. But if you forgot about it, here's a recap of what we did.
Today Ms.Yoo taught us about dividing polynomials. She started first in drawing a polynomial tiles in the projector thing
If you didn't get that, we used division to figure out the missing polynomials in the multiplication statement. So in order to do that you divide the answer(6x-8x) to the first statement (2x) in order to get the answer (3x-4)
Then after that Ms.yoo showed us a problem using Dividing Polynomials.
-What is the ratio of the surface area to the radius of cylinder
If you didn't get that, in order to do this problem you need to divide the area of the cylinder by the ratio to get you answer.
That's pretty much all the things we did today, the rest of the class, Ms.Yoo showed us our homework se we can work on it
Homework
-Read 272-274
-CYU 2, 4or5, 6or7, 8-18
-workbook 7.3
-7.3 extra practice sheets
While working on that, Mr.Backe told us the things we needed for out stash-its
STASH ITS
-all chp. 5 material with 2 test signed
-the mathlinks for chp.7 in the textbook not the sheets
(I think that's pretty much it, if you have more that you knoe then feel free to comment.)
For the next scribe I choose JAI...
Thanks for reading my Scribe....
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Question # 23
Tuesday, November 24, 2009
Hey guys, I got to do number 23 for the homework blog and and it wasn't easy to do.
The question was;
a.) Write a subtraction statement involving two negative fractions or negative mixed numbers so the the difference is -4/3.
b.) share your statement with a classmate. ( Now for this one sharing it in the blog is like sharing it with a classmate so I already did this question.)
Now writing a equation is really a hard thing for me to do especially if i don't understand the question. For this one I understood the question because it's asking me to make a subtraction question that equals to - 4/3 and the equation has to involve two negative fraction eitheir a normal or mixed fraction.
Now of course both fraction has to have the denominator of 3 because the answer has a denominator of 3 and the numerator has to have a -4 as an answer.
Labels:
Fractions,
francisM9-05,
Homework
Rational NUmbers
Friday, November 6, 2009
What is a rational number?
Any number of arithmetic: Any whole number, fraction, mixed number or decimal; together with its negative image.
A rational number is a nameable number, in the sense that we can name it according to the standard way of naming whole numbers, fractions, and mixed numbers. "Five," "Six thousand eight hundred nine," "Nine hundred twelve millionths," "Three and one-quarter," and so on.
A rational number can always be written in what form?
As a fraction
a b
, where a and b are integers (b 0).
An integer itself can be written as a fraction: b = 1. And from arithmetic, we know that we can write a decimal as a fraction.
When a and b are positive, that is, when they are natural numbers, then we can always name their ratio.
Hence the term, rational number. N
ow a fraction can always be expressed as a decimal.
Either the decimal will terminate -- as 1/4 = .25;
or the decimal will have a predictable pattern -- as 1/11 = .090909. . .
A rational number, then, can always be expressed as such a decimal. -->
Any number of arithmetic: Any whole number, fraction, mixed number or decimal; together with its negative image.
A rational number is a nameable number, in the sense that we can name it according to the standard way of naming whole numbers, fractions, and mixed numbers. "Five," "Six thousand eight hundred nine," "Nine hundred twelve millionths," "Three and one-quarter," and so on.
A rational number can always be written in what form?
As a fraction
a b
, where a and b are integers (b 0).
An integer itself can be written as a fraction: b = 1. And from arithmetic, we know that we can write a decimal as a fraction.
When a and b are positive, that is, when they are natural numbers, then we can always name their ratio.
Hence the term, rational number. N
ow a fraction can always be expressed as a decimal.
Either the decimal will terminate -- as 1/4 = .25;
or the decimal will have a predictable pattern -- as 1/11 = .090909. . .
A rational number, then, can always be expressed as such a decimal. -->
Labels:
Decimals,
francisM9-05,
Homework,
Rational Numbers
Question 20

The question that I got to do for the textbook is #20
I Never really liked this question but it was assinged so I have to do it and I didn't get it on how to do this so the one you're going to see is pretty much a guess
And the question was:
Research to find out the current price of gasoline in Calgary, Alberta. It is 300 km from Calgary to Edmonton. How much would it cost to drive this distance in a car with a fuel consumption of 5.9 L/100 km than in a car with a fuel consumption of 9.4 L/100 km? Give your answer in dollars, expressed to the nearest cent.
--We need to find out which one is better to travel from Calgary to Edmonton
*We know that the Gas price in Calgary is $88.9 as I searched in the computer.
*We're trying to find out which one is better to use, the 5.9L/100km or 9.4/100km
*NOw the rest of the things I'm going to do is only on my desire and I don't know if it's right.
=)I'm going to multiply each of them by 3 because there'e 300 km and it's /100 km so 100*3 would equal 300. And of course what we do with this we also have to do with the other one.
--5.9*3= 17.7
*_*Now we have to multiply the asnwer by the gas price but of course we can't multiply 17.7 by 88.9 because that means multiplying $88.9 by 17.7 and there's no gas that cost that much so we have to turn 88.9 so that means dividing the number by 100 and we get 0.889 so now we can solve it
So that means that it wouls cost you $15.73 to get from Calgary to Edmonton
Of course we have to do the other on to:
We now have to do the 9.4/100km and we have to do the same method with this one like what we did on the other one.
--(9.4)(3) = 28.2
*-*Now that we have 28.2, we have to multiply it again with the cent (0.889)
--(28.2)(0.889)=24.9852
* and of course we get the answer $24.9852 as the total amount of getting to Calgary to Edmonton using the litres.
Now we need to subtract the difference between the answer between (15.7535) and (24.9852)
So now the Difference between the litres B is $9 from Litres A
So the answer is:
So that means that 5.9/100km is the better one to use than 9.4/100km
And that it's better to use the 5.9 to get to Edmonton that the 9.4That's All and thank you for reading my posts..........*_*
Labels:
Decimals,
francisM9-05,
Homework,
Rational Numbers
Scribe post for October 14
Thursday, October 15, 2009
( Sorry that i just posted this now because my internet wasn't working properly so i'm sorry just i just posted the scribe today)
Hi everyone and today we reviewed on the house thingy. I thought that the test for the surface area was today but it wasn't so i'm really glad about that. The first thing that Mr Backe told us is if we have any any question for the homework and no one raised their hands so we just moved in to the house problem. Instead of explaning you thigns i'll just show it in picture.
Hi everyone and today we reviewed on the house thingy. I thought that the test for the surface area was today but it wasn't so i'm really glad about that. The first thing that Mr Backe told us is if we have any any question for the homework and no one raised their hands so we just moved in to the house problem. Instead of explaning you thigns i'll just show it in picture.
This house concludes all this shapes so in order to figure the total of the house you need to do each shape
Sorry that it's really hard to see but if you click on the picture i'm sure it should be okay.
Those are pretty much all we did. Then Mr backe assinged us another homework of the house thing.
more homework.
-mathlink p.35
-chapter review 36-37
-mathlink on p.39
-chapter 1 practise test (I think)
-------------------------------
all in work book
-Workbook 1.3 p.89
-vocablink p.11 chapter review p.12-13
And there's the things that's due on monday
- 2 test signed (1%)
- Self evaluation (2%)
- Foldables (complete) (2%)
- 3 Matlinks
(p..15)
(25)
(35)
(39)
- Journal complete and one entry taht shows your best learning (5%)
That's about all that we did for today and as of I heard the math test is on friday i think.
The next scribe I pick is Marc Dava
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francisM9-05,
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Why is a 360, 360?
Monday, October 5, 2009
Have you aver wondered why is a 360 a full circle, I mean it could also be like 180 or 60 degrees so why is it 360?
Our "numbering" system for time and angles originally came from the Babylonians. They had a base number system of 60. One of the reasons is that 60 is divisible by 2, 3, 4, 5, 6, 10 and 12 and etc.
This divisibility means that you don't have to deal with fractions as much (a very difficult thing to do with a non decimal system - think about doing decimal calculations using Roman numerals!!)
So why 360? Well it's not very hard because 6 x 60 = 360.
Another theory was there is more to this than the six sixes for the 360 fromthe Babylonians. It has to do with Claudius Ptolemy (100-170 AD), who divided the circle into 360 parts for his sine table. He actually used the length of the chord for each central angle in steps of 1/2 degree in a circle of radius 60 rather than sines.
Our "numbering" system for time and angles originally came from the Babylonians. They had a base number system of 60. One of the reasons is that 60 is divisible by 2, 3, 4, 5, 6, 10 and 12 and etc.
This divisibility means that you don't have to deal with fractions as much (a very difficult thing to do with a non decimal system - think about doing decimal calculations using Roman numerals!!)
So why 360? Well it's not very hard because 6 x 60 = 360.
Another theory was there is more to this than the six sixes for the 360 fromthe Babylonians. It has to do with Claudius Ptolemy (100-170 AD), who divided the circle into 360 parts for his sine table. He actually used the length of the chord for each central angle in steps of 1/2 degree in a circle of radius 60 rather than sines.
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360 degrees,
francisM9-05
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