Scribe Post for April 8, 2010

Hello lets start right away, today in class Mr. B talked about question 19 in the math text book. which looked like this:

Now here is the formula


Time to plug in the numbers



Next you see if you can cancel out anything.


As you can see, 9.8 is being divided by s. On the other side 29.16 is being multiplied by s. So since multiply and divide are opposites they the s's cancel out each other.

Last part is to solve it


Well that's it for that question, Mr B. also mentioned a interrupted graph which looks like this

When there is no set of data for a large portion after the origin you use an interrupted graph.

For the rest of class was a work period for the homework that is due Monday, which is :

6.3 Textbook ALL SYK, ALL CYU
Practice 4-7, 8, and 10
Apply 13, 15, 17
Extend 19, 20 or 21
Math link
Extra Practice
Work Book

That is all due Monday, and don't forget to study for the test on Monday

That's it for my scribe, sorry I didn't get it done before 7 Mr. B. Sorry if I made a mistake, and if you can't see the pictures just click on them.

Scribe Post for December 2, 2009

Hello 9-05 I'm back once again with another scribe. Today Mr B showed us how to find LCM (Lowest Common Multiple). This is what he showed us...
*CLICK TO MAKE IMAGE BIGGER*

So Mr. B gave us 3 numbers. After those numbers we put the prime numbers that are below 10. Next we figured out how many times each prime number goes into each number. For example the number 3. The prime numbers below 10 are 2,3,5 and 7. So 2 goes into 3 no times so you put and exponent of 0 on the number 2. Then you do that for the next number which is 3, so 3 goes into 3 one time so you put an exponent of 1. Then 5 goes into 3 no times so you put an exponent of 0 for the number 5. Lastly 7 goes into 3 no times so you put an exponent of 0 on the number 7.

Then you do that for the next number which is 5. Which will give you 2^0, 3^0, 5^1, and 7^0


Now for the number 21 its different if you break down 21 into 2 numbers that multiply, you would get 3x7. Then you see put your prime numbers into that. Which would get you 2^0, 3^1, 5^0, and 7^1. So for bigger numbers its easier to break it down then to put the prime numbers into the multiples.

Well that's pretty much what we did in math today. Mr B just gave us more examples and explained it more clear. Well that's my scribe, sorry if their are any mistakes and if it is confusing. For the next scribe it will be FRANCIS M.

Question 15

Hello 9-05 sorry for my late post, but better late then never right. Well Mr. B assigned me number 15. So here we go.

So the question is

Predict the next three numbers in the pattern,

Here is the question and answer

*CLICK TO MAKE IT BIGGER*
(bottom right corner says " To find the next number take the last number and add 5/8")

Now here is the second question
*CLICK TO MAKE IT BIGGER*

Well sorry for the short and late post also I'm sorry if my pictures are confusing/unreadable. Comment if you find anything mistakes. Well until my next blog post goodbye for now

Scribe Post for November 12, 2009

Hello 9-05 its been a while since we had a scribe. With all the things that get in the way such as in service and take your kids to work day. But now were back! Today we played a card game using decimals and Mr. B wrote a web with the word fractions in the middle which should look a little something like this
*click on it to make it bigger*

The other thing we did in class was we played a card game. We first took out the face cards, jokers and 10's. So there are 2 players and they both get 2 cards. Even if both players have cards its only one persons turn. Say that its player 1's turn and we deal 2 cards to each person they flip over the card and they get

Player 1:
2 and 3

Player 2:
4 and 7

after the players get their cards they flip a coin which is red on one side and yellow on the other (red is positive and yellow is negative or vise-versa). If both players flip and both get red which is positive player 1 (since its his turn) has to try to make a number closest to zero using 2.3 and 4.7 (since those are closest you can get to zero). Lets say he puts the numbers together and gets 2.4 (4.7 - 2.3 = 2.4). Next both players get 2 cards again but this time its player 2's turn, so say they get

Player 1
5 and 7

Player 2
6 and 7

so they both flip the coin again but this time they both get negative. Since its player 2's turn he/she has to try to get as close to 0 by using -5.7 and -6.7. Lets say he gets 1 [-5.7-(-6.7) = 1]. Now you can see that Player 1 has 2.4 and Player 2 has 1 whoever is closest to zero which is Player 2 he gets two points . After you just repeat the process over.

Well that was my scribe, or my attempt at scribe. Hopefully you guys understand it or at least some of it. I'm not perfectly sure on the instructions of the game. Also I'm sorry for my messy writing in the picture. Soo now for the next scribe. THE NEXT SCRIBE IS.....KRISSA. So that's all sorry for the late night post.

Question Number 26

Hello, well here is my late post on question number 26

Four points, A, B, C, and D, have the following coordinates:

A(0.75,0.81)

B(0.75,-0.65)

C(-1.22,-0.65)

D(-1.22,0.81)

what is the area of the quadrilateral ABCD, to the nearest

hundredth of a square unit

Well the picture should look something like this

just click the picture to make it larger

the length and with would be

L=1.97

W=1.46

now for the solving

L x W = A

1.97 x 1.46 = A

A=2.8762

So the area of the rectangle is 2.88 units squared

sorry that my post is so short and sorry if there are any mistakes.